0=1500p-50p^2

Solution for 0=1500p-50p^2 equation:

0=1500p-50p^2

We move all terms to the left:

0-(1500p-50p^2)=0

We add all the numbers together, and all the variables

-(1500p-50p^2)=0

We get rid of parentheses

50p^2-1500p=0

a = 50; b = -1500; c = 0;
Δ = b2-4ac
Δ = -15002-4·50·0
Δ = 2250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2250000}=1500$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1500)-1500}{2*50}=\frac{0}{100}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1500)+1500}{2*50}=\frac{3000}{100}
=30
$